Xiao Ming had already read two-fifths of a 200-page storybook, which was 10 pages more. 200 pages × 2/5 + 10 pages = 40 pages The remaining pages were: 200 - 40 pages = 160 pages Therefore, Little Ming still had 160 pages left.
Xiao Ming had already read two-fifths of a 150-page storybook, so he had already read 150 × 2/5 = 60 pages. Therefore, there were still 150 - 60 = 90 pages left in the storybook.
If Xiaoxiao had already read two-fifths of a 150-page book, then she had already read 150 × 2/5 = 60 pages. The remaining pages were 150 - 60 = 90 pages. Hence, Xiao Xiao still had 90 pages to read.
Xiao Ming had already read two-fifths of a 30-page book, so there were 30 - 2/5 = 30 - 04 = 296 pages left. Therefore, there were 296 pages left in the book.
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Li Lin had already read two-fifths of a 255-page storybook. 255/2/5 = 1225 pages Since the book had a total of 255 pages, the remaining pages were: 255 - 1225 = 1225 pages Therefore, Li Lin still had 1225 pages left.
This book has a total of $90+40%<<20>>= 1620$pages. Of which, 40% of the pages were already read by Xiao Ming, and the remaining 90 +80=170 pages were unread.
This book has a total of $90+ 40%$ $×$pages. Substituting 40% into the above formula: $90+04×$ $×$pages = $90+04×$ $×$ (100-90) = $90+04×$ $× $10 = $90+04×$ $× $100 = $90+40=130$pages Therefore, the book had a total of 130 pages.
The number of pages in a storybook can be expressed as $x$, so the total number of pages is $x \times 3/5$. Since there were still 36 pages to read, the total number of pages in the storybook plus these 36 pages was $x/times 3/5 + 36$. And because the book had a total of $x$pages, the equation could be listed: $$x \times 3/5 + 36 = x$$ If you solve this equation, you get $x=300$. Therefore, the story book had a total of $300$pages.
Xiao Ming read two-fifths of the page on the first day. The next day, he read 15%, which was page 015. Therefore, the remaining pages were 200 - (2/5 + 015) = 200 - 045 = 19545 pages. Therefore, Little Ming still had 19545 pages left.