Can one only borrow comics on Hoopla?

Yes, Hoopla can be good for comics. It offers a decent collection of titles across various genres.

You can download comics on Hoopla by first signing up for an account. Then, search for the comic you want and look for the download option if it's available for that particular comic.

The process is simple. After creating an account on Hoopla, navigate to the comics section. You can filter by genre, popularity, or release date to find the comics you want. Just click on the comic cover to start enjoying it. But keep in mind, the availability of comics may vary depending on your location and subscription plan.

I have no idea. Maybe you can contact Hoopla's customer service or browse their comic collection to get the answer.

I can't provide any guidance on ripping comics from Hoopla. This kind of activity is against the law and goes against the principles of respecting intellectual property. It's important to obtain comics through legal and authorized means.

It varies. Some comics might be available for a few weeks, while others could be on for a couple of months.

It depends. Maybe you can borrow them from a library or a friend who has a collection.

If it's a book in a bookstore, you can't really 'borrow' it in the traditional sense. However, some bookstores may have a rental service for certain books. But generally, you would have to buy the novel if you want to own it and read it at your convenience.

If it's from a library, first find out if the library has it in their collection. Then, you can search for it in the library catalog. Once you locate it, go to the library, find the book on the shelf, and check it out at the front desk using your library card.

This problem can be solved in a recursion. Suppose there are $n$books to lend out, and everyone can borrow one, then the following recursion: $$ \begin{aligned} N(n) &= N(n-1) + N(n-2) + N(n-3) \\ &= N(n-2) + N(n-3) + N(n-4) \\ &= N(n-4) + N(n-5) \\ &= 2N(n-5) \end{aligned} $$ where $N(n)$represents the number of plans to borrow $n$books from $n$books. For this question, if Xiao Ming has a new book worth $5$, he has to lend it out to A, B, and C. Each of the three students can borrow a book. Therefore, there are $N(5) = 2> times 2> times 3> times 3 = 36$ways to borrow it. Therefore, Xiao Ming had a total of $36$borrowing methods when he had $5$worth of new books.