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The page numbers of a novel were arranged with 2871 numbers. How many pages were there in this novel?

2024-09-19 23:58
1 answer

Let's say this novel has x pages. Since the page number used 2871 numbers, the following page numbers can be listed: 2 3 4 2871 The page number of each page was composed of numbers, and each number appeared in the previous number of the page number, and the number of times each number appeared was not repeated. Therefore, the arrangement of the numbers on each page was as follows: 2 × 1 + 3 × 1 + 4 × 1 + + 2870 × 1 + 2871 × 1 = 2871 × (2 + 1 + 4 + + 1) = 2871 × n where n is the number of times the number appears in the page number. Therefore, this novel has a total of x pages. According to the above calculation, we can get: x = 2871 × n Substituting x into the above formula gives: x = 2871 × n × (2 + 1 + 4 + + 1) / 2 In the above formula, n × (2 + 1 + 4 + + 1) is the sum of the number of times the number appears in the page number divided by 2 is the average number of times the number appears in the page number. The above formula was simplified to: x = 2871 × n × (n + 1) / 2 Since n is an integral number, x must be a multiple of 2871. At the same time, because each number in the page number does not repeat, n must be an odd number. Therefore, this novel had a total of 2871 pages.

Is this destiny?

Is this destiny?

Sarah Hill is an introvert who does not want to attract attention. Other than mad coding skills, Sarah knows how to throw a punch. She believes that her biggest problem is the existence of the hacker Omega and her world flips upside-down when the most popular guy on campus approaches her. What does he want? Why her? (Ah, Sarah, that is only the beginning.) JoAnna Hill easily makes friends with her bubbly personality. Some call her a mad scientist, but she prefers ‘Dr. Hill’, because that is what she is. JoAnna is an excellent markswoman who can snipe out any target and she is wondering if her prince charming will ever come. Sophia Hill is the voice of reason, their pillar of support. She is a confident CEO who knows how to get what she wants. Sophia’s degree in law combined with amazing capabilities to analyze the situation and plan ahead make her the perfect strategist (to achieve a goal without ending up in jail). This is a story of three Hill sisters who are navigating through challenges while they uncover the complicated story behind their maternal side of the family. And their father is not a simple man either. Every sister is different, and so are their relationships. They all have in common: trust and belief that if they work together, anything is possible. Mature content! 18+ ***SPOILER? - START *** The story starts with a focus on the youngest sister (Sarah). After about 100 chapters, the oldest sister (Sophia) gets in the romantic spotlight. JoAnna finds herself pulled into romance last, at about 200 chapter mark. ***SPOILER? - END *** Excerpt from the novel... "Do you believe in destiny?", Sarah broke the silence. "Destiny?" Aiden didn't expect such a question. "Yes. The thing that is meant to happen, and there is nothing you can do to prevent it. And when it does happen, everything feels right." "Why would you ask me such a thing?" "Until a few weeks ago I would say that there is no such thing as destiny. That we are all masters of our lives and that everything depends on our actions, or lack of it. But I can't help but wonder: why did I not push you away? ... Why does it feel like everything will be OK as long as we are together? ... You are a piece of me that I never knew was missing. Is this destiny?" "Mmm... if that is destiny, then I approve it.", Aiden lightly kissed Sarah's shoulder and rested his chin on it. --- 1st WARNING!!! Contains descriptions of intimate scenes. If you are not comfortable with that, don’t read it! --- 2nd WARNING!!! This is my first novel! :) --- ***** I own the cover. ***** Check out my other novels: * "Accident Prone" * "Amara - Reunion" * "The Alpha's Bride" * "The Supreme Alpha"
4.9
2127 Chs
How Am I Still Alive?

How Am I Still Alive?

Spiritual Qi Resurgence, Gods descending? Continuous disasters, all living beings suffering? What does it have to do with me? I'm just a patient with an incurable disease, who's been given up on treatment and has a countdown to death. Embarking on the path of exorcising demons and annihilating immortals with my crippled body is not for the sake of protecting my family and country, but because the hazardous duty pay is too tempting, especially the compensation... "This Evil Gods profession system is cursed, even if there's smooth progress in the early stages, the practitioners will eventually commit suicide..." "Give me a set." "This Demon Sword poisons its user and has already taken ninety-nine lives..." "Give me two, and also that man-eating demonic helmet, soul-devouring blood claws, get me a set." "This Magic Potion is harmful to heaven and earth..." "Enough talk, I'll take them all!" However, the problem is, why am I still alive after taking on all these high-risk missions, stepping on every risk, and doing every deadly task? 【Congratulations, congratulations! Ranked first among the Top Ten Heroes Who Moved the World...】 "...Heavens, wasn't the average life expectancy in this line of work three and a half years? I've been here for one cycle of three years after another, I'm almost an S-level hunter, the first of the top ten heroes! Why am I still alive? I just want to make an honor sacrifice, scam some compensation! Is that so hard?!"
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1403 Chs

There were 297 numbers on the page number of a novel. How many pages were there in this novel?

1 answer
2024-09-08 20:59

This problem could be solved through mathematical methods. Assuming that the novel has $n$pages, then each page has $p$numbers, where $1'le p 'le n$. According to the page number of the question, a total of $297$numbers can be listed as follows: $$n\times p + n - 1 = 297$$ To simplify it: $$n(p+1) = 297 - 1 = 296$$ Since $n$is an integral,$p+1$must be a multiple of $296$. At the same time, since $1'le p 'le n$,$p+1$must be a multiple of $12' ldotsn'$. Therefore, the following restrictions can be obtained: $$p+1> text {is a multiple of $1$but not a multiple of $2$} p+1> text {is a multiple of $2$but not a multiple of $3$}& ldots p+1> text {is a multiple of $n$but not a multiple of $n-1 $}$$ According to these constraints, the value range of $p+1$can be obtained: $$135791113\ldotsn$$ Substituting these values into the equation $n(p+1) = 297 - 1$gives: $$n(n+1) = 297 \times (n+1)$$ To simplify it: $$n^2 + n - 296 = 0$$ By solving this second order equation, one could get: $$n = \frac{296\pm\sqrt{296^2-4\times1\times296}}{2\times1} = \frac{296\pm294}{2}$$ Since $n$is an integral number,$n$can only take two values: $$n = 44 n = 43$$ So this novel has a total of $44$or $43$pages.

The page number of a book required 1995 numbers. How many pages were there?

1 answer
2024-09-20 23:50

Assuming that the book had n pages, the page number of the book should be a sequence of n numbers. Since the page number needed to satisfy 1995 numbers, the page number of the book must contain at least 1995-1=1994 numbers. Next, we need to determine the smallest number in the page number. We can sort the numbers from 1 to 1994 and find the smallest number in the page. According to the sequence of numbers, the smallest number in the page number is 4. Therefore, the page number of the book contained four numbers: Page number = 4 2 9 5 Substituting these four numbers into the 1995 numbers, we get: 1995 = 4 * 2 * 9 * 5 = 720 * 5 = 3600 Therefore, the book had a total of 3600 pages.

The page number of a book required 1995 numbers. How many pages were there?

1 answer
2024-09-11 06:45

This was a rather special page number that used 1995 numbers. Usually, the page number of a book was composed of the number of pages and the number of pages. The number of pages was only composed of 0 to 9, while the number of pages was composed of 1 to 999. Therefore, if we assume that the page number of this book is composed of page numbers, then its page number range should be 1 to 999, a total of 9990 pages. However, due to the use of 1995 numbers, the book actually had 9991 pages.

A book had 200 pages. How many numbers were needed to number the pages?

1 answer
2024-09-11 15:35

A book has 200 pages, and if you want to use numbers to number the pages, you'll usually start with 1 and increment each page by one number. Therefore, the page number could be prefixed with 1, 2, or 3199, and the page number could be postfixed with 200. For example, if the page number of a book is "123456","1" represents the first page,"2" represents the second page, and so on,"3" represents the third page,"4" represents the fourth page,"5" represents the fifth page,"6" represents the sixth page,"7" represents the seventh page,"8" represents the eighth page,"9" represents the ninth page,"10" represents the tenth page,"11" represents the eleventh page,"12" represents the twelfth page,"13" represents the thirteenth page,"14" represents the fourteenth page," 15"" 16 " represents the 15th page," 17 " represents the 17th page," 18 " represents the 18th page," 19 " represents the 19th page," 20 " represents the 20th page, and add the page number with the " 0 ".

If there was a 1000-page book and 40 pages were torn out, could the sum of all the page numbers of these 40 pages be 2021?

1 answer
2024-09-16 00:26

This question involves some calculations and logical reasoning. I can try to give a reasonable answer. Assuming that each page of the 1000-page book has a page number, the sum of all the page numbers on the 40 pages can be expressed as: 40 sheets x total page number of 40 sheets = 40 x 1000 = 40000 page numbers Now we add up the 40000 pages: 40000 pages + 1 page = 40101 pages Please note that we are assuming that each page has a unique page number. If some of these 40 sheets of paper do not have corresponding page numbers, then these page numbers will appear on other sheets of paper, and their sum may be different. So if we can't determine the exact order and number of these pages, we can't be sure if the sum of these pages will equal 2021. But if we assume that each page has a unique page number and that these page numbers are arranged in order, then we can calculate the sum of all the page numbers in these 40 pages: 40 sheets x total page number of 40 sheets = 40 x 1000 = 40000 page numbers The sum of all page numbers = 40000 page numbers + 1 page = 40101 page numbers Therefore, if every page has a unique page number and these page numbers are arranged in order, then the sum of all the page numbers in these 40 pages cannot be equal to 2021.

A book had 200 pages, so how many numbers were needed?

1 answer
2024-09-11 15:37

The numbers needed to paginate a book with 200 pages are: 200 pages/number per page (for example, 1 page = 1 number) = 100 numbers Therefore, a book with 200 pages would need 100 numbers to number the pages.

How many numbers do you need to page a 450-page novel?

1 answer
2024-09-21 08:26

The number of numbers needed to paginate a 450-page novel depended on the format and arrangement of the pages. The following are some possible scenarios: 1. Arrange by chapter: If the novel has 10 chapters, there will be a page number between each chapter. A total of 10 page numbers will be needed. If the novel had 450 chapters, it would need 4500 pages. 2. Arrange by page: If the novel has 450 pages but there are no page numbers between each page but an individual number, then you need to arrange a page number for each page, a total of 450 pages. 3. Arrange by word count: If the total word count of the novel is 450000 words, then you can make a total page number for the novel according to the word count and then make a page number for each chapter or page. A total of 450 pages were required. Therefore, to answer this question, one needed to know the specific page numbering and the total number of words.

The novel had a total of 320 pages. How many numbers were there? How many times had the number '1' appeared?

1 answer
2024-09-15 13:17

It didn't matter how many times 1 appeared. What was important was the plot and character development of the novel.

5. How many numbers do you need to print the pages of a 200-page book?

1 answer
2024-09-18 14:25

The number of pages needed to print a 200-page book is: 200 pages/page (page) = 200/15 = 16 Therefore, the number of page numbers required to print a 200-page book was 16.

How to cite a graphic novel with no page numbers?

1 answer
2024-10-11 15:46

You could mention the title, author, and publication date. Maybe also describe the specific section or scene you're referring to.

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