The total number of pages in the book was $30+30=60$pages. The number of pages read is $2x$, and the number of unread pages is $3x$. where $x$is an integral number. On the first day, the ratio of pages read to unread was $2:3, so $2x=3x+30. The solution is $x=10$. Therefore, the number of pages read is $2x=20$, and the number of unread pages is $3x=30$. So this novel has a total of $60$pages, I've read $20$pages, I haven't read $30$pages.
Suppose the book has a total of $n$pages, the number of pages read is $m$, and the number of unread pages is $n-m$. According to the question, the ratio of the number of pages read to the number of pages unread is two to three, and the following equations can be listed: $$ \begin{cases} m = 2(n-m) \\ m + 30 = n \end{cases} $$ Transforming the second equation into $n = 4m + 30$and replacing it into the first equation gives $2m = 30$. The solution is $m = 15$. So the book has a total of $n=50$pages, the number of pages read is $m=20$, and the number of unread pages is $n-m=30$.
According to the plot of the novel, Wang Xiao had read about 70% of the novel before dinner, so he had read about 72% of the novel by the time he read eight pages after dinner. Since the ratio of the number of pages seen and the number of pages not seen was the same, Wang Xiao's number of pages not seen would increase by 8 pages, which was 16% of the content. Therefore, the ratio of the number of pages Wang Xiao had read before dinner to the number of pages he had not read was 1/7. After dinner, it was 167, which was about 2667%.
Xiao Dong read 3/5 of the book on the first day, which was 0.6 times the volume of the book. The next day, he read another 20 pages, which was equivalent to 1/5 of the entire book, which was 0.2 times the volume of the entire book. Therefore, the number of pages Little Dong had read was: The number of pages read = the volume of the book x the number of days read-the total number of pages = 06 × volume of the book × 1 - 02 × volume of the book = 02 × the volume of the book Since the total number of pages in the book did not change, the number of pages that Xiao Dong had read was 0.2 times that of the book.
Let the total number of pages of the book be x, then Xiaowang read 125% on the first day = 0125x 136 pages on the second day, so Xiaowang read a total of 0125x + 136 pages. The ratio of the remaining pages to the number of pages seen is 3:5, so the number of pages left is 0875x- 136, and the number of pages seen is 0875x- 136 + 0125x = 09x. According to the question, the ratio of the remaining pages to the number of pages seen is 3:5, so the equation can be written: 0875x - 136 = 3(09x) Solve the equation: 0125x = 192 x = 144 Therefore, the total number of pages in this book was 144.
Wang Hong read a book on the first day, read 3/7 of the total pages, and the next day, read 1/4 of the total pages. How much of the book was left? Answer: The total number of pages in the remaining books is 3/7 of the total number of pages plus 1/4, which means the total number of pages is 8/7 plus 1/4, which is 9/11. Therefore, Wang Hong still had 9/11 of the book to read.
Xiao Ming read a storybook. The number of pages he read before dinner was one-fifth of the number of pages he did not read. After dinner, he read another six pages. At this time, the number of pages he read was four of the number of pages he did not read. According to the story, Xiao Ming had already read a part of the storybook before dinner, which was one-fifth of the unread pages. Therefore, the number of pages he read before dinner was one-fifth of the total number of unread pages. After dinner, he read another 6 pages. The number of pages he had read was one-fourth of the total number of pages he had not read, which was one-fourth of the total number of pages he had not read. Therefore, Xiaoming had read 11/10 of the storybook before and after dinner, which was also 11/10 of the unread pages. This ratio could be expressed as: Number of pages not seen/number of pages seen = 11/10 The number of unread pages is the ratio of the total number of pages, the number of read pages is the number of unread pages.
Xiao Ming read a storybook. The number of pages he had read before dinner was 1/5 of the number he had not read. After dinner, he read another 6 pages. This was the number of pages he had read, which was 1/4 of the number he had not read.
On the first day, Xiaofang read the book's 51 pages, and the remaining pages were $51/div2 = 25$. The next day, he read another 10 pages and the remaining pages were $25 + 10 =$35. At this point, the ratio of pages seen to pages not seen is 2:3, which can be expressed as $25:35=2:3$. Therefore, Xiaofang had read the book for $2+3=5$days and still had $35-5=28$pages left.
Xiao Ming reads a book on the first day, 20% of the total number of pages, and the number of pages read on the second day is 5/4 of the number of pages read on the first day, leaving 110 pages Assuming that the total number of pages in this book is x: I read 20% on the first day, which is 02x pages. I read 5/4x pages the next day because I read more pages the next day than the first day The remaining pages are x -02x- 5/4x = 110 pages Solve the equation: x = 1100 Therefore, the total number of pages in this book is 1100. Xiaoming read 200 pages on the first day and 300 pages on the second day.
Dongdong read a total of x pages at the end of the first week. The total number of pages in this book is 150, so: At the end of the second week, Dongdong had read (150 - x) pages. Dongdong hadn't finished reading 150 pages by the end of the second week, so he had read (150 - x) pages less than or equal to 150 pages. And because Dongdong had read page X in the first week: x = 150 - x + 1 = 149 The solution was x = 1, so Dongdong read a total of 149 pages in the first week. Dongdong had read (150 - 1) = 149 pages by the end of the second week. Therefore, Dongdong read a total of 149 pages in this book, and there was still one page left at the end of the second week.