Xiaofang had already read three-fifths of the book, so the remaining pages were the total number: Remaining pages/total = (1 - 3/5)/total = 2/5 Therefore, the ratio of the remaining pages to the total number was 2/5:1 = 4:5.
The total number of pages in this book was 80 + 31 = 111. Therefore, the number of pages that Xiaofang had read accounted for the total number of pages in this book: 111 pages = 1 / 11 In other words, the number of pages that Xiaofang had read accounted for 1/11 of the total number of pages in the book.
Xiaofang read 15 of the book on the first day and read 10 pages on the second day, so she read a total of ${1}{5} +{1 = 15}$pages. Assuming that the book has a total of $x$pages, then Xiaofang has read a total of $x \times \frac{1}{5} + x \times \frac{10}{1 = 10x + 50}$pages. At this time, the ratio of the number of pages read to the number of pages not read is 2, which means that the number of pages left by Xiaofang is twice the number of pages in the book, which is $x/times 2 = 10x + 50$. The solution is $x = 105$, which means that the book has 105 pages. Xiaofang read 15 pages on the first day and 10 pages on the second day. She read 25 pages in total.
Xiaofang read a story book for a few days, and the ratio of the number of pages read to the number of unread pages is 3:5. Then, she read 27 pages. You can set the number of pages read as x the number of unread pages as 5x/3, so there is: x + 27 = 5x/3 The solution is x = 18 Therefore, Xiaofang had already read 18 pages, and there were 5 × 18/3 = 30 pages. She then read another 27 pages, so she had read 18 + 27 = 45 pages and still had 30 unread pages.
On the first day, Xiaofang read the book's 51 pages, and the remaining pages were $51/div2 = 25$. The next day, he read another 10 pages and the remaining pages were $25 + 10 =$35. At this point, the ratio of pages seen to pages not seen is 2:3, which can be expressed as $25:35=2:3$. Therefore, Xiaofang had read the book for $2+3=5$days and still had $35-5=28$pages left.
Xiaoming reads a storybook, Xiaofang reads a science book. The number of pages in a storybook is 75% of that in a science book. Xiaoming reads 15 pages a day, Xiaofang reads 18 pages a day. If Xiaoming and Xiaofang had a total of 100 pages, then they would read 100 * 15 / 100 = 15 pages a day. The remaining pages were 75% of the pages of the science book, which was 75 * 18 / 100 = 15 pages. Since the number of pages in the story book was 75% of the number of pages in the science book, the remaining pages were 75 / 75 = 1 page. Therefore, Xiaoming and Xiaofang read a total of 15 + 1 = 16 pages a day. They only read one page a day, which meant that they couldn't read the rest of the pages.
This novel should be called " One Hundred Years of Solitude."
Xiao Hong read 30% in the first week and 55 pages in the second week. The ratio of the number of pages read to the total number of pages is 2:3. We can set the total number of pages of this book as x pages. According to the question, Xiao Hong had already read 30% of the first week, which was 03x pages. In the second week, she had read 55 pages, so she had already read 03x + 55 pages. The ratio of the number of pages seen to the total number of pages is 2:3, so there is: 03x + 55 = 2/3x Solve the equation: 13x + 55 = 2/3x 13x - 2/3x = 55 01x = 55 x = 550 Therefore, the total number of pages in this book was 550.
Xiaolan had already read 2/3 of the total number of pages in the book, so she had already read (2/3) × 240 = 80 pages. The remaining pages were 240 - 80 = 160 pages. Therefore, there were still 160 pages left to read.
Let's assume that the total number of pages in this book is x. The number of pages that Naughty had already read was x +5 + 24, which was a total of x +5+24. The remaining pages make up two-thirds of the total number of pages, so there are: x÷5+24 + x/2 = x The above formula was simplified: x/2 + 24 = x After the reduction, it was obtained: x/2 = 24 Solution: x = 48 Therefore, the total number of pages in this book was 48.
Suppose the book has a total of $n$pages, the number of pages read is $m$, and the number of unread pages is $n-m$. According to the question, the ratio of the number of pages read to the number of pages unread is two to three, and the following equations can be listed: $$ \begin{cases} m = 2(n-m) \\ m + 30 = n \end{cases} $$ Transforming the second equation into $n = 4m + 30$and replacing it into the first equation gives $2m = 30$. The solution is $m = 15$. So the book has a total of $n=50$pages, the number of pages read is $m=20$, and the number of unread pages is $n-m=30$.