The book had a total of 108 pages.πI recommend a novel called Dream Casting 2005. It tells the story of programmer Lin Fan returning to 2005. In this life, he wants to go further and see more scenery. The book had a total of 108 pages, which seemed to be able to satisfy Xiaofang's requirement that the ratio of the number of pages she had read to the number of pages she had not read was 2:5. She had to read 27 pages, which was exactly half of the novel. I hope you like this fairy's recommendation. Muah ~π
If Xiaofang had already read 20 pages and the remaining pages were 5, then the total number of pages Xiaofang had read was 20 * 2 = 40 pages. If Xiaofang read another 27 pages, the total number of pages she read would be 40 + 27 = 67 pages. This novel has a total of 67 pages. Xiaofang has already read 20 pages, and the remaining pages are 47 pages.
The total number of pages that Xiaofang had read was 56. The remaining pages were 56-1=55 pages. The number of pages that Xiaofang had read was 55Γ7=355 pages.
The storybook has a total of 100 pages. The number of pages that have been read is four times that of the number of pages that have not been read. The known number of pages seen = the number of pages seen + the number of pages left, which was 4 unseen pages = the number of pages seen + the number of pages left. Transferring the items would yield 5 pages remaining = 4 pages viewed, which meant that the remaining pages = 4 pages viewed divided by 5. Since the story book has a total of 100 pages, 4 pages viewed/5 = 8 pages remaining. Thus, there were still eight pages left.
On the first day, Xiaofang read the book's 51 pages, and the remaining pages were $51/div2 = 25$. The next day, he read another 10 pages and the remaining pages were $25 + 10 =$35. At this point, the ratio of pages seen to pages not seen is 2:3, which can be expressed as $25:35=2:3$. Therefore, Xiaofang had read the book for $2+3=5$days and still had $35-5=28$pages left.
Xiaofang read a story book for a few days, and the ratio of the number of pages read to the number of unread pages is 3:5. Then, she read 27 pages. You can set the number of pages read as x the number of unread pages as 5x/3, so there is: x + 27 = 5x/3 The solution is x = 18 Therefore, Xiaofang had already read 18 pages, and there were 5 Γ 18/3 = 30 pages. She then read another 27 pages, so she had read 18 + 27 = 45 pages and still had 30 unread pages.
This book has a total of $30+ 30> times 3/7=60$pages.
Assuming that there were still x pages left, the number of pages that had been read would be 420 - x. According to the question, the number of pages that have been read is the remaining three-quarters, so the following equation can be written: 420 - x = 3/4 (420 - x) To simplify it: x = 396 Therefore, there were still 396 pages left.
Xiaofang read 15 of the book on the first day and read 10 pages on the second day, so she read a total of ${1}{5} +{1 = 15}$pages. Assuming that the book has a total of $x$pages, then Xiaofang has read a total of $x \times \frac{1}{5} + x \times \frac{10}{1 = 10x + 50}$pages. At this time, the ratio of the number of pages read to the number of pages not read is 2, which means that the number of pages left by Xiaofang is twice the number of pages in the book, which is $x/times 2 = 10x + 50$. The solution is $x = 105$, which means that the book has 105 pages. Xiaofang read 15 pages on the first day and 10 pages on the second day. She read 25 pages in total.
If the number of pages seen is x, the remaining pages are 200-x. According to the meaning of the question, the equation can be listed: x = 60% (200-x) To simplify it: x = 60% Γ 200 - 60% Γ x To solve the equation: 120 - 30% Γ x = 200 30% Γ x = 80 x = 240 Therefore, the number of pages he had seen was 240.
According to the ratio of the number of pages read to the number of pages unread on the first day was 2:7, the number of pages unread was 2/7 of the number of pages read. Because he read 42 pages the next day, the number of pages read was 42/2/7=91(pages), and the number of unread pages was 42/(2/7)=63(pages).