Little Wang read a book. On the first day, he read 12.5% of the whole book. On the second day, he read 136 pages. The ratio of the remaining pages to the number of pages he had read was 3:5...
Let the total number of pages of the book be x, then Xiaowang read 125% on the first day = 0125x 136 pages on the second day, so Xiaowang read a total of 0125x + 136 pages. The ratio of the remaining pages to the number of pages seen is 3:5, so the number of pages left is 0875x- 136, and the number of pages seen is 0875x- 136 + 0125x = 09x. According to the question, the ratio of the remaining pages to the number of pages seen is 3:5, so the equation can be written: 0875x - 136 = 3(09x) Solve the equation: 0125x = 192 x = 144 Therefore, the total number of pages in this book was 144.
Dongdong read a book on the first day, the ratio of the number of pages he had read to the number of pages he had not read was 2 to 3. The next day, he read another 30 pages, and the number of pages he had not read was this one
The total number of pages in the book was $30+30=60$pages. The number of pages read is $2x$, and the number of unread pages is $3x$. where $x$is an integral number. On the first day, the ratio of pages read to unread was $2:3, so $2x=3x+30. The solution is $x=10$. Therefore, the number of pages read is $2x=20$, and the number of unread pages is $3x=30$. So this novel has a total of $60$pages, I've read $20$pages, I haven't read $30$pages.
Wang Hong read a book. On the first day, he had read 3/7 of the total number of pages. On the second day, he had read 1/4 of the total number of pages. How many pages of the book had he not read?
Wang Hong read a book on the first day, read 3/7 of the total pages, and the next day, read 1/4 of the total pages. How much of the book was left? Answer: The total number of pages in the remaining books is 3/7 of the total number of pages plus 1/4, which means the total number of pages is 8/7 plus 1/4, which is 9/11. Therefore, Wang Hong still had 9/11 of the book to read.
Xiaofang read a story book. On the first day, she read 1/5 of the whole book, and on the second day, she read 10 pages. The ratio of the number of pages read to the number of pages not read was 2.
Xiaofang read 15 of the book on the first day and read 10 pages on the second day, so she read a total of ${1}{5} +{1 = 15}$pages. Assuming that the book has a total of $x$pages, then Xiaofang has read a total of $x \times \frac{1}{5} + x \times \frac{10}{1 = 10x + 50}$pages. At this time, the ratio of the number of pages read to the number of pages not read is 2, which means that the number of pages left by Xiaofang is twice the number of pages in the book, which is $x/times 2 = 10x + 50$. The solution is $x = 105$, which means that the book has 105 pages. Xiaofang read 15 pages on the first day and 10 pages on the second day. She read 25 pages in total.
Xiaodong read a book. On the first day, he read 3/5 of the book, and the next day he read 20 pages. At this time, he had read the number of pages in the book.
Xiao Dong read 3/5 of the book on the first day, which was 0.6 times the volume of the book. The next day, he read another 20 pages, which was equivalent to 1/5 of the entire book, which was 0.2 times the volume of the entire book. Therefore, the number of pages Little Dong had read was: The number of pages read = the volume of the book x the number of days read-the total number of pages = 06 × volume of the book × 1 - 02 × volume of the book = 02 × the volume of the book Since the total number of pages in the book did not change, the number of pages that Xiao Dong had read was 0.2 times that of the book.
Xiaofang read a story book. On the first day, she read 51 pages of the book, and on the second day, she read 10 pages. The ratio of the number of pages she had read to the number of pages she had not read was 2:3.
On the first day, Xiaofang read the book's 51 pages, and the remaining pages were $51/div2 = 25$. The next day, he read another 10 pages and the remaining pages were $25 + 10 =$35. At this point, the ratio of pages seen to pages not seen is 2:3, which can be expressed as $25:35=2:3$. Therefore, Xiaofang had read the book for $2+3=5$days and still had $35-5=28$pages left.
Dongdong reads a book on the first day. The ratio of the number of pages he has read to the number of pages he has not read is two to three. The next day, he reads 30. At this time, the number of pages he has not read is this
Suppose the book has a total of $n$pages, the number of pages read is $m$, and the number of unread pages is $n-m$. According to the question, the ratio of the number of pages read to the number of pages unread is two to three, and the following equations can be listed: $$ \begin{cases} m = 2(n-m) \\ m + 30 = n \end{cases} $$ Transforming the second equation into $n = 4m + 30$and replacing it into the first equation gives $2m = 30$. The solution is $m = 15$. So the book has a total of $n=50$pages, the number of pages read is $m=20$, and the number of unread pages is $n-m=30$.
Xiao Ming is reading a book. He had read 20% of the total number of pages on the first day. The number of pages read on the second day was 5:4 compared to the number of pages read on the first day. There were still 110 pages left to be read…
Xiao Ming reads a book on the first day, 20% of the total number of pages, and the number of pages read on the second day is 5/4 of the number of pages read on the first day, leaving 110 pages Assuming that the total number of pages in this book is x: I read 20% on the first day, which is 02x pages. I read 5/4x pages the next day because I read more pages the next day than the first day The remaining pages are x -02x- 5/4x = 110 pages Solve the equation: x = 1100 Therefore, the total number of pages in this book is 1100. Xiaoming read 200 pages on the first day and 300 pages on the second day.
Xiao Ming read a book. On the first day, he read 1/6 of the book, the second day, he read 24 pages, and the third day, he read the total number of pages in the previous two days.
Xiao Ming read a book on the first day, he read 1/6 of the whole book, the second day, he read 24 pages, the third day, he read the total number of pages in the previous two days If he read 24 pages the next day, he would read (24 div6) = 4 pages the next day. The rest of the books had 5/6 pages. Xiaoming read 1/6 pages on the first day, so he read (5/6 div1/6) = 30 pages on the first day. Xiao Ming's remaining book had 1/6 pages. The number of pages he read the next day was 4 + 30 = 34. Xiao Ming's remaining book had 1/6 pages. The number of pages he read on the third day was 34 + 24 = 58. Therefore, on the third day, Xiao Ming read the entire book's 58 + 6 = 9 pages.
Xiao Lin read a book. On the first day, he read three-fifths of the total number of pages. On the second day, he read 20%, leaving 20 pages. How many pages is this book?
Let the total number of pages in this book be x pages: - I read 3/5x pages on the first day. -20% read the next day =02x pages. According to the meaning of the question, the remaining pages were x-(3/5x+02x)=20 pages. Substituting x=50 pages gives: - I read 3/5 x 50 pages =30 pages on the first day. - The next day, I read 02 x 50 pages =10 pages. Therefore, the book had a total of 50 pages.
Xiao Lin read a book. On the first day, he read three-fifths of the total number of pages. On the second day, he read 20%, leaving 20 pages. How many pages is this book?
The total number of pages in this book is x. On the first day, I read three-fifths of the total number of pages, which is 3/5x pages on the first day. Reading 20% the next day meant reading 20% x 3/5 x = 2/5 x pages. Because he read 2/5x pages the next day, the remaining pages were 1 - 2/5x = 3/5x pages. Because Kobayashi read 3/5x pages, the total number of pages Kobayashi read was 3/5x + 2/5x = 5/5x pages. And because there were still 20 pages left in Kobayashi's book, 20 = 3/5x + 2/5x solved the equation to get x = 120. So this book has 120 pages.