Assuming that the book had a total of $n$pages, then according to the question, Little Light finished reading $15/times 4 = 60$pages in 4 days. The remaining pages are $n - 60$. And because the total number of pages in the book is 3/5 of the book, there are: $$n - 60 = 3/5 \times n$$ The above formula was simplified to: $$n = 225$$ Therefore, the book had a total of 225 pages.
Assuming that the book has $x$pages, the number of pages that Xiaoming reads on the fourth day is $x$multiplied by $1/13$. Because Xiao Ming had read for 4 days, the number of pages he read plus the remaining pages equals the total number of pages: $$ x + (x \times 1/13) + 90 = x $$ To simplify it: $$ x \times 12 - x \times 1/13 + 90 = 0 $$ Solve this equation: $$ x = 130 $$ Therefore, the book had a total of 130 pages.
If Xiao Ming reads a book every day for 15 pages and 24 days, then the book has a total of 15 * 24 = 360 pages. If I read 20 pages a day, how many days can I finish it? Assuming that the book has x pages, the total number of pages that Xiaoming needs to read is 20 * x days. Because Xiao Ming needed to read 360 pages, there were: 20 * x = 360 Solve this equation: x = 180 Therefore, Xiao Ming needed to read 180 pages to finish the book. If he read 20 pages a day, he would need 180 * 20 days = 3720 days to finish the book.
If Xiao Ming reads 15 pages a day, the total number of pages he needs is: 15 pages/day x 24 days = 360 pages Therefore, Xiao Ming needed to read 360 pages to finish it in 24 days. The number of days required to read 20 pages a day is: 20 pages/day x days = 20 days Therefore, Xiao Ming needed to read for 20 days to finish the book.
The book had a total of $58+ 5'times 10=630$pages.
According to the question, Cockroach read 5 days *20 pages/day =100 pages, and the remaining 15 pages of the book are equal to the total number of pages-100 pages that have been read, so the total number of pages is: 100 pages +15 pages =115 pages. The answer was page 115.
The number of pages that Xiaoming reads on the first day is 20% of the whole book. The number of pages that he reads on the second day is 20% of the remaining pages. The percentage of the number of pages that he reads on the second day can be calculated as follows: The number of pages that Xiaoming read on the first day was 20% of the entire book. In other words, the total number of pages that Xiaoming read was: Total pages = 20% × pages of the book = 02 × pages of the book The number of pages that Xiao Ming read the next day was 20% of the remaining pages. In other words, the total number of pages that Xiao Ming read was: Total pages = 20% x Remaining pages = 02 x Remaining pages Then, the percentage of the number of pages that Xiao Ming read the next day in the total number of pages in the book can be calculated as: The number of pages Xiao Ming read the next day divided by the total number of pages in the book × 100% = 02 divided by 08 × 100%= 25% Therefore, the number of pages that Xiao Ming read the next day accounted for about 25% of the total number of pages in the entire book.
Mao Mao reads a book and reads 30 pages a day in 8 days. Therefore, the total number of pages in this book is 30 × 8 = 240 pages. If I read 40 pages a day, how many days can I finish it in advance? Using the ratio method to answer: To calculate the number of days you can read 40 pages a day compared to 30 pages a day, you can use the ratio method: Reading 40 pages a day was 40 - 30 = 10 pages more than reading 30 pages a day. Therefore, the number of days required to finish reading this book was 240 pages/10 pages/day = 240 days. Substituting this result into the original formula: 8 days/240 days = 0037125, which meant that reading 30 pages a day was about 37125 days earlier than reading 40 pages a day. Therefore, by reading 40 pages a day, he could advance by 0.037125 + 37125 = 47125 days. The answer was about four days in advance.
Assuming the book has $x$pages: - $40$on the first day. - The next day, he read $40/times 2 = 80$pages. - On the third day, if you read $3/8$on $40$pages, you would read $10$pages. Because there was still $5/8 left, there was: $$ 40 + 80 + 10 = \boxed{120} $$ So this book has 120 pages.
Xiaoming reads a storybook for the first 4 days, reads 25 pages a day, then reads 40 pages a day, and reads for 6 days, just finishing it. How many pages does Xiaoming read on average every day? The number of pages in the storybook was fixed. The number of pages read in the first four days was 25 x 4 = 100 pages, and the remaining pages were 100 - 6 x 25 = 35 pages. Therefore, Xiaoming reads an average of 35 pages a day.
Little Red reads a book 15 pages a day, and after 4 days, there is still 3/5 of the book left. We can assume that this book has x pages. According to the question, Little Red had read a total of $4/times 15 = 60$pages in 4 days. The remaining pages are 3/5 of the book, so there are: $$ 60\div 3/5=24 $$ Therefore, the book had 24 pages.