A novel had a total of 336 pages, and Xiao Ming was prepared to finish it in eight days. How many pages would he read on average every day?

Xiao Ming needed to finish reading the remaining 260 pages in 5 days, so he needed to read 260 pages per day divided by 5 days = 52 pages.

Reading 30 pages a day in 8 days would allow one to finish reading this literary masterpiece. 30 pages/day x 8 days = 240 pages If Kobayashi wanted to finish it in six days, the total number of pages he needed to read was: 240 pages/6 days = 40 pages/day As a result, Kobayashi read an average of 40 pages a day.

If Xiaoming reads 72 pages in the first 4 days, then Xiaoming's total page count in the first 4 days is 72 pages. Reading 29 pages every day for the next 6 days would mean that the total number of pages for the next 6 days would be 29 pages x 6 days = 171 pages. Therefore, Little Ming's total page count in the last six days was 171 pages. Little Ming read 171 pages per day for the next 6 days, 6 days = 27 pages. Therefore, Xiao Ming read an average of 27 pages a day.

If a novel has 404 pages and you read an average of 40 pages a day, you can calculate how many days it takes to finish it. 404 pages/40 pages/day = 102 days Therefore, it would take about 102 days to finish a 404-page novel.

Assuming that this literary masterpiece had 1000 pages, Kobayashi could read 30 pages a day, so he could read 320 pages in eight days. If Kobayashi wanted to finish it in six days, the total number of pages he needed to read was: 1000 pages/6 days = 16667 pages/day Since there is no prime number difference between reading 30 pages per day and reading 16667 pages per day, we can assume that Kobayashi reads 167 pages per day. In this way, the total number of pages of literary classics that Xiao Lin needed to read in six days was: 167 pages/1 day = 167 pages Therefore, Kobayashi needed to read 167 pages a day to finish reading this literary masterpiece in six days.

Assuming that this literary masterpiece has $N$pages, Kobayashi has to read it in 6 days, so the total number of pages needed is $N$. Reading $30$pages a day meant that Kobayashi could read $30/times 6 = 180$pages in 6 days. In order to find out how many pages Kobayashi reads on average every day, we can divide the total number of pages by the total number of days: $$ \frac{N}{8} = \frac{180}{8} = 25 $$ As a result, Kobayashi read an average of $25 per day.

If you can finish a storybook by reading 12 pages a day and 15 days, then the average number of pages in this storybook is: 15 days/ 12 pages/day = 15 pages/day Therefore, if Li Xiaolin wanted to finish reading this storybook in 10 days, he should read it on average every day: 10 days/ 15 pages/day = 6 pages/day In other words, Li Xiaolin should read 6 pages a day instead of 12 pages a day.

(1)There were still 80 pages left. (2)The remaining pages had to be read within four days, an average of 80 pages per day. This was equivalent to 80/170 = 05 days per page. Therefore, in the remaining 80 pages, you need to look at 80/05 = 16 days, 80/05 = 16 days, 80/05 = 16 days, and 80/05 = 24 days (rounded to two decimals). The final answer was that it took him 16 + 24 = 40 days to read the remaining 80 pages on the 16th and 24th days.

Xiao Ming had read 280 pages in the past 5 days, so he had already read 280 x 5 = 1400 pages. The book has 500 pages, so the remaining pages are 500 - 1400 = -700 pages. This means that Xiaoming has to reread the 700 pages of the book in the next 7 days, but he can choose to start reading on any day. If Xiao Ming chose to start reading from the sixth day, then the number of pages he needed to read every day was 700/6 = 100 pages. Therefore, Xiao Ming needed to read 100 pages on average every day.

Little Light had already read 59 pages. The remaining pages were 95 - 59 = 36 pages. Little Light needed to read 36 pages a day divided by 4 days = 9 pages per day. Therefore, Little Light needed to read nine pages a day to finish the remaining 36 pages in four days.