The number of pages that Xiaoming reads on the first day is 20% of the whole book. The next day, he reads 20% of the remaining pages. The number of pages that he reads on the second day accounts for 100% of the total pages of the whole book.

Xiao Ming read 20% of the total number of pages on the first day of reading a book, which means that the total number of pages multiplied by 20% equals 20% of the total number of pages. On the second day, the ratio of pages read on the first day was 5:4, which meant that half of the total pages read on the second day was 25% of the total pages. Therefore, Xiao Ming read the total number of pages multiplied by 25% the next day, which was equal to the total number of pages multiplied by 5%. Divide the total number of pages by 5 to get the number of pages that Xiaoming read the next day divided by 5. That is, the total number of pages divided by 5 multiplied by 40% equals the total number of pages multiplied by 10%. Therefore, Xiao Ming read the total number of pages multiplied by 10% the next day, which was equal to the total number of pages multiplied by 5.

Suppose the book has a total of $n$pages, the number of pages read is $m$, and the number of unread pages is $n-m$. According to the question, the ratio of the number of pages read to the number of pages unread is two to three, and the following equations can be listed: $$ \begin{cases} m = 2(n-m) \\ m + 30 = n \end{cases} $$ Transforming the second equation into $n = 4m + 30$and replacing it into the first equation gives $2m = 30$. The solution is $m = 15$. So the book has a total of $n=50$pages, the number of pages read is $m=20$, and the number of unread pages is $n-m=30$.

Xiao Ming reads a novel. If he reads 35 pages a day, he will finish the whole book one day later than the stipulated date. If he reads 40 pages a day, he will read 5 pages less on the last day. We can set the total number of pages of the novel as x and the specified date as d, then the total number of pages that Xiaoming needs to read is x/35 + x/40 - 1. According to the question, Xiaoming needs to read d books, so there are: x/35 + x/40 - 1 = d Transferring the terms of the equation gave: x/100 = d Therefore, Xiao Ming needed to read 100 pages a day to finish the novel by the stipulated date. If you read 35 pages a day, you would need an extra two days to finish the novel. If you read 40 pages a day, you would need an extra three days to finish the novel. After considering all, Xiaoming needed to read 37 pages a day to finish the novel according to the stipulated date. On the last day, he had to read 5 pages less.

Xiao Ming read 3/8 of the book on the first day, which was 042675 or 42675% of the book. The next day, he read 18 pages, and the remaining pages were 5/8 of the book, which was 075 or 75%. Suppose the book has x pages: 3/5 of the total number of pages read = (x * 3/8 + 18) / x = 3/5 To simplify it: x = 42 * 8 / 3 = 96 Therefore, the book had a total of 96 pages.

Let the total number of pages of the book be x, then Xiaowang read 125% on the first day = 0125x 136 pages on the second day, so Xiaowang read a total of 0125x + 136 pages. The ratio of the remaining pages to the number of pages seen is 3:5, so the number of pages left is 0875x- 136, and the number of pages seen is 0875x- 136 + 0125x = 09x. According to the question, the ratio of the remaining pages to the number of pages seen is 3:5, so the equation can be written: 0875x - 136 = 3(09x) Solve the equation: 0125x = 192 x = 144 Therefore, the total number of pages in this book was 144.

Xiao Ming read a story book and read a total of 38 pages in the first two days and 54 pages in the next three days. We can use the total number of pages to deduct the number of pages in the first two days and the next three days to get the average number of pages that Xiaoming reads every day. Total pages = 38 + 54 = 82 In the previous two days, he had read 38 pages, so the ratio of the number of pages read in the previous two days to the total number of pages was 38 pages/ 82 pages = 047875, which could be approximately expressed as 047875. In the next three days, a total of 54 pages were read. The ratio of the number of pages read in the next three days to the total number of pages was 54 pages/ 82 pages = 06667, which could be approximately expressed as 06667. Therefore, on average, Xiaoming reads 047875 × 2 + 06667 × 3 = 016533 × 2 + 023333 × 3 = 039167 × 2 + 050938 × 3 = 089715 × 2 + 010785 × 3 = 1575 × 2 + 0192 × 3 = 27533 every day, which is about 275. Therefore, Xiao Ming read an average of 275 pages a day.

Xiaoming reads a storybook for the first 4 days, reads 25 pages a day, then reads 40 pages a day, and reads for 6 days, just finishing it. How many pages does Xiaoming read on average every day? The number of pages in the storybook was fixed. The number of pages read in the first four days was 25 x 4 = 100 pages, and the remaining pages were 100 - 6 x 25 = 35 pages. Therefore, Xiaoming reads an average of 35 pages a day.

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If Xiao Ming reads 15 pages a day, the total number of pages he needs is: 15 pages/day x 24 days = 360 pages Therefore, Xiao Ming needed to read 360 pages to finish it in 24 days. The number of days required to read 20 pages a day is: 20 pages/day x days = 20 days Therefore, Xiao Ming needed to read for 20 days to finish the book.

If Xiao Ming reads a book every day for 15 pages and 24 days, then the book has a total of 15 * 24 = 360 pages. If I read 20 pages a day, how many days can I finish it? Assuming that the book has x pages, the total number of pages that Xiaoming needs to read is 20 * x days. Because Xiao Ming needed to read 360 pages, there were: 20 * x = 360 Solve this equation: x = 180 Therefore, Xiao Ming needed to read 180 pages to finish the book. If he read 20 pages a day, he would need 180 * 20 days = 3720 days to finish the book.