A book has 80 pages. Kobayashi read 1/5 of the book on the first day. Which page should he start reading the next day
Kobayashi read one-fifth of the book on the first day, which was page 25. So the next day he should start reading from page twenty-five.
Xiaodong read a book. On the first day, he read 3/5 of the book, and the next day he read 20 pages. At this time, he had read the number of pages in the book.
Xiao Dong read 3/5 of the book on the first day, which was 0.6 times the volume of the book. The next day, he read another 20 pages, which was equivalent to 1/5 of the entire book, which was 0.2 times the volume of the entire book. Therefore, the number of pages Little Dong had read was: The number of pages read = the volume of the book x the number of days read-the total number of pages = 06 × volume of the book × 1 - 02 × volume of the book = 02 × the volume of the book Since the total number of pages in the book did not change, the number of pages that Xiao Dong had read was 0.2 times that of the book.
Little Min read an extra-cursory book. On the first day, she read 24 pages. On the second day, she read 3 pages less than the first day. Which page should Little Min start reading on the third day?
According to the information given by the question, Little Min read 24 pages on the first day and read 3 pages less on the second day, so she read 23 pages on the second day. Since she had read page 23 the next day, Min had read page 23/times 2 = 46 after the next day. Since Min read 24 pages on the first day, she should have read $24 - 46 =-22$pages after the first day. Because Min read 24 pages on the first day and 23 pages on the second day, she should start from the remaining pages on the third day, which is $-22 + 24 =-8$pages. Therefore, Little Min should start reading from page $-8$on the third day.
Little Min read a 900-page storybook. On the first day, she read 124 pages. On the second day, she read 37 pages less than the first day. On the third day, which page should she start reading?
Little Min read a 900-page storybook, and on the first day, she read 124 pages. On the second day, she read 37 pages less than the first day. Assuming Min reads x pages the next day, the number of pages left on the second day is 900-x. According to the first day of reading page 124, the following equation can be listed: 124 + x = 900 - x + 37 Solve the equation: 151 = 867 Therefore, the number of pages that Little Min read on the third day should be a multiple of 867. Since 900 is an even number, 867 is a multiple of 900, so Min should start reading from page 867.
Zhang Lin was reading a 234-story book. He started from the first page and read 12 pages a day. He had already read 11 days. Which page should he read on the 12th day?
The information you provided is not detailed enough. Please provide more background information such as the type of story book, author, and storyline so that I can better help you.
A book has a page, read 15 pages a day, and finish it in a week
A book has a page A. Reading 15 pages a day in a week is just enough. Assuming a book has page A and 15 pages a day, the number of days needed to finish the book in a week is: a ÷ 15 = (a + a) ÷ 2 = 2a / 2 + a / 2 Transferring items can be sorted out: 2a / 2 = a + a / 2 To simplify it: a = 4 Therefore, a book had four pages, and 15 pages a day was just enough to finish it in a week.
Xiao Ming read a book with 240 pages. He had already read 4 pages. On average, he would read 15 pages a day. Which page would Xiao Ming start reading on the fifth day?
Xiao Ming read an average of 15 pages a day. He had already read 4 pages, so he still needed to read 4/15 = 02 days. Because Xiao Ming needed to watch for 5 consecutive days, he could move the days that he needed to watch forward by 5 days. 2 days + 4 days = 6 days Therefore, Little Ming needed to start from page 6, which was page 11.
Ming has a 170-page book. He read 80 pages in the first 4 days. If he wants to finish reading it in a week, how much should he read every day from the fifth day?
Ming has a 170-page book. He read 80 pages in the first 4 days. If he wants to finish it in a week, how many pages will he read every day from the 5th day onwards? From the 5th day onwards, read x pages every day, where x represents the number of pages that the nickname reads every day from the 5th day onwards. Reading 170 pages a day required 170 pages divided by 5 days = 34 pages per day. Therefore, from the fifth day onwards, Ming Xiao needed to read 34 pages a day.
Xiao Ming read a book. On the first day, he read 10% of the book, the second day, he read 35%, and the third day, he read 44 pages. This book…
How many pages are there in this book? According to the title, Xiaoming read 10% of the book on the first day, which was 10% of the book divided by 100% = 1/10 pages. Xiao Ming read 35% of the book the next day, which was 35% of the book divided by 100% = 035 pages. Xiao Ming read 44 pages of the book on the third day, so the number of pages in the book can be calculated by the following formula: 1 ÷ (1/10 + 035 + 1/10) = 44 Solve the equation: Number of pages in the book = 44 × 100%/(1 + 035 + 1) = 3520 Therefore, this book had a total of 3520 pages.
Dongdong reads a book on the first day. The ratio of the number of pages he has read to the number of pages he has not read is two to three. The next day, he reads 30. At this time, the number of pages he has not read is this
Suppose the book has a total of $n$pages, the number of pages read is $m$, and the number of unread pages is $n-m$. According to the question, the ratio of the number of pages read to the number of pages unread is two to three, and the following equations can be listed: $$ \begin{cases} m = 2(n-m) \\ m + 30 = n \end{cases} $$ Transforming the second equation into $n = 4m + 30$and replacing it into the first equation gives $2m = 30$. The solution is $m = 15$. So the book has a total of $n=50$pages, the number of pages read is $m=20$, and the number of unread pages is $n-m=30$.
1/5 of a book was read on the first day. The ratio of reading on the second day to reading on the first day was 5:4. There were 66 pages left unread. How many pages were there in the book?
If the book has x pages: I read 1/5x page on the first day I read (5/6)x pages the next day, where 5/6x means that the number of pages read on the first day accounts for 5/6 of the number of pages read on the second day. The remaining pages are x - 1/5x - (5/6)x = 66 pages According to the above equations, a set of linear equations with two variables can be listed: 1/5x + (5/6)x = 66 Solution:x = 460 Therefore, the book had 460 pages.