Xiaoming reads a book on the first day, reading 20% of the total number of pages, the number of pages read on the second day and the number of pages read on the first day is 5:4

The number of pages that Xiaoming reads on the first day is 20% of the whole book. The number of pages that he reads on the second day is 20% of the remaining pages. The percentage of the number of pages that he reads on the second day can be calculated as follows: The number of pages that Xiaoming read on the first day was 20% of the entire book. In other words, the total number of pages that Xiaoming read was: Total pages = 20% × pages of the book = 02 × pages of the book The number of pages that Xiao Ming read the next day was 20% of the remaining pages. In other words, the total number of pages that Xiao Ming read was: Total pages = 20% x Remaining pages = 02 x Remaining pages Then, the percentage of the number of pages that Xiao Ming read the next day in the total number of pages in the book can be calculated as: The number of pages Xiao Ming read the next day divided by the total number of pages in the book × 100% = 02 divided by 08 × 100%= 25% Therefore, the number of pages that Xiao Ming read the next day accounted for about 25% of the total number of pages in the entire book.

Xiao Ming reads a book on the first day, 20% of the total number of pages, and the number of pages read on the second day is 5/4 of the number of pages read on the first day, leaving 110 pages Assuming that the total number of pages in this book is x: I read 20% on the first day, which is 02x pages. I read 5/4x pages the next day because I read more pages the next day than the first day The remaining pages are x -02x- 5/4x = 110 pages Solve the equation: x = 1100 Therefore, the total number of pages in this book is 1100. Xiaoming read 200 pages on the first day and 300 pages on the second day.

Xiao Ming read 3/8 of the book on the first day, which was 042675 or 42675% of the book. The next day, he read 18 pages, and the remaining pages were 5/8 of the book, which was 075 or 75%. Suppose the book has x pages: 3/5 of the total number of pages read = (x * 3/8 + 18) / x = 3/5 To simplify it: x = 42 * 8 / 3 = 96 Therefore, the book had a total of 96 pages.

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Li Hua read a 500-page extra-cursory book. On the first day, he read 15% of the total number of pages. On the second day, he read 10% of the total number of pages. 1 5 On the third day, he read 20% of the total number of pages.

Xiaofang read 15 of the book on the first day and read 10 pages on the second day, so she read a total of ${1}{5} +{1 = 15}$pages. Assuming that the book has a total of $x$pages, then Xiaofang has read a total of $x \times \frac{1}{5} + x \times \frac{10}{1 = 10x + 50}$pages. At this time, the ratio of the number of pages read to the number of pages not read is 2, which means that the number of pages left by Xiaofang is twice the number of pages in the book, which is $x/times 2 = 10x + 50$. The solution is $x = 105$, which means that the book has 105 pages. Xiaofang read 15 pages on the first day and 10 pages on the second day. She read 25 pages in total.

According to the ratio of the number of pages read to the number of pages unread on the first day was 2:7, the number of pages unread was 2/7 of the number of pages read. Because he read 42 pages the next day, the number of pages read was 42/2/7=91(pages), and the number of unread pages was 42/(2/7)=63(pages).

Wang Hong read a book on the first day, read 3/7 of the total pages, and the next day, read 1/4 of the total pages. How much of the book was left? Answer: The total number of pages in the remaining books is 3/7 of the total number of pages plus 1/4, which means the total number of pages is 8/7 plus 1/4, which is 9/11. Therefore, Wang Hong still had 9/11 of the book to read.

On the first day, Xiaofang read the book's 51 pages, and the remaining pages were $51/div2 = 25$. The next day, he read another 10 pages and the remaining pages were $25 + 10 =$35. At this point, the ratio of pages seen to pages not seen is 2:3, which can be expressed as $25:35=2:3$. Therefore, Xiaofang had read the book for $2+3=5$days and still had $35-5=28$pages left.

Let's say the book has x pages. 30% read on the first day = 03x pages, the remaining pages are x-03x = 07x pages. The next day, I read 4 pages less than the first day, so I read 07x-4 pages the next day. According to the meaning of the question, the remaining pages are 44 pages, so there are: 07x-4 = 44 Solve the equation: 07x = 48 x = 64 So this book has 64 pages.